What is the error left of''must have class?

Error C2228: Left rear must have a class / structure / union , fifteen times? This is an advanced class example that mimics the incredibly simple registration / browsing process for school classes. I am getting error C2228: left with `` must have class / struct / union everywhere in two .cpp files.

Why does c2228 say must have class / struct?

This is appropriate (but not correct) for more annoying parsing, because you will find that this is caused by the same rule of the language, namely that operators are function declarations when they are most likely parsed as the accepted answer. Object, whose initializer is likely to be a clause without parentheses, i.e. () can be value-initialized.

This is how you solve the problem of concatenating the class structure of the required classes

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Here are some simple ways that can help you with the error of merging class structure.

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I am a longtime Java user, learning C ++ with Qt and have a very good understanding of how methods work. Right now I am trying to understand databases and tried to simplify my code with a header. Usually in Java, I could only have one class named With databasecontrol, a void method that would do whatever I wanted. For example, when I add a worker to the database, I do it without hesitation. I would createal an instance of the class, making it like

  DatabaseControl something myDBControl = new DatabaseControl ();

  myDBControl.addEmploye ();

, which will display a series of input fields allowing the user to enter information about the employee – name, department, etc.

  DatabaseControl classpublicly:    Database Management ();    ~ DatabaseControl ();    // methods    addEmployee ();;

I don’t have any specifications in my constructors because I just want to call the “addEmployee” systems in my head office as shown above. In the same header file I buy this in my class declaration

  void DatabaseControl :: addEmployee () {QSqlQuery-qry;bool ok;QString firstName = QInputDialog :: getText (NULL, "QInputDialog :: getText ()",                                     "Employee starts with last name:", QLineEdit :: Normal,                                     NULL, & OK);if (ok &&! firstName.isEmpty ())another    QMessageBox msgBox;    msgBox.setWindowTitle ("Error");    msgBox.setText ("An error occurred while adding an employee.  nReason: the employee's company was not specified.");    msgBox.exec ();QString lastName corresponds to QInputDialog :: getText (NULL, "qinputdialog :: gettext ()",                                    "Employee Name:", QLineEdit :: Normal,                                     NULL, & OK);     or not (ok &&! lastName.isEmpty ())         qry.prepare("INSERT employee name)" (name, "VALUES (: f1 ,: f2)");         name query); bindvalue (: f1 ", qry.bindValue (: f2", lastName);        qry.exec ();          another         QMessageBox msgBox;         msgBox.setWindowTitle ("Error");         msgBox.setText ("The employee could not be added.  nReason: the employee's name was not specified.");         msgBox.exec ();

  void mainwindow :: on_addemployee_clicked ()   DatabaseControl myDBControl ();    myDBControl.addEmployee ();

I thought I just ran the addEmployee tool that I wrote in the header file. However, when I compile, I get a specific error: Error C2228: to the left of .addEmployee must contain class / struct / union

I’ve looked at other error cases above and I really don’t understand what’s wrong with them, and it seems to me that this is due to my poor understanding of methods in C ++ just because I know something in Java like ours. work without it (provided that the signal in the header is correct, which may not be entirely clear)

2 minutes to read.

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The operand to the left of period (.) is not a program or structure union.

  // C2228.cppint i;structure Spublicly:    member of type int; s, * ps equals & s;int main ()   i.Member matches 0; // C2228 my partner is not in class   ps.member = 0; // C2228 ps3 - pointer to structure   see member = 0; // people are a type of structure   ps-> member = 0; // ps finally points to the Will s structure

This surprising error also occurs when using incorrect syntax when using managed extensions. While in other Visual Studio languages you can use the display in operator to access a member of any managed class, the C ++ pointer in the article means that you must use the -> operator to access any member:

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É Assim Que Você Resolve O Problema De Concatenar A Estrutura Da Classe Com As Classes Necessárias
Detta är Sättet Att Lösa Problemet Med Att Sammanfoga Högskolestrukturen För De Obligatoriska Klasserna
Вот как вы можете решить проблему объединения структуры образовательной среды требуемых классов
이것이 실제로 필요한 클래스의 해당 클래스 구조를 연결하는 문제를 해결하는 방법입니다.
Dit Is Echt Hoe Je Het Probleem Oplost Door De Klassenstructuur Van De Vereiste Klassen Samen Te Voegen
Así Es Como Alguien Resuelve El Problema De Concatenar La Disposición De Clases De Las Clases Requeridas
W Ten Sposób Rozwiązujesz Problem łączenia Struktury Klasyfikacji Wymaganych Klas
Questo è Probabilmente Il Modo In Cui Risolvi Il Problema Concatenando La Struttura Delle Classi Delle Classi Richieste
So Lösen Sie Das Problem Der Verkettung Der Tarifstruktur Der Benötigten Klassen
Voici Comment Vous Résolvez Le Problème Réel De Concaténer La Structure De Classe De Leurs Classes Requises