How To Fix Java Exception Example When Descriptor File Was Not Found

 

Here are some simple steps that should help you solve the problem in the Java Descriptor File Exception Not Found example.

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Indicates that an attempt to open the identified image with the specified path name failed. This exception is thrown by all FileInputStream, FileOutputStream, and RandomAccessFile constructors when the file with the specified path does not exist.

 

 

java.io.FileNotFoundException, which was often the exception that occurs when our company tries to access a file. FileNotFoundExcetion is definitely triggered by the constructors RandomAccessFile, FileInputStream, and FileOutputStream. FileNotFoundException is thrown at runtime, so it must be a checked exception. We can handle some exceptions with Java code, and we mark the code carefully so that this exception will not be thrown.

public class FileNotFoundException Extends IOException use ObjectInput, ObjectStreamConstants

• FileNotFoundException (): A FileNotFoundException exists as an empty message.
• FileNotFoundException (String s): A FileNotFoundException exists with a verbose message.

It has no process. Now let’s deal with the hierarchy of the entire class, i.e. FileNotFoundException extends IOException, which extends the Exception class, which extends the concrete Throwable class, and further extends the Object class.

There are basically 2 scenarios that will throw a FileNotFoundException. Now lookm on them with a highlight:

1. If the specified file is not available at the specified location, this error will occur.
2. If the specified file is not available, for example if it is write protected, you should be able to read the file, but not individually. When we try to improve it, an error occurs, or if it turns out that the file you are trying to access was created by another program, this error usually occurs.

If the specified file is not open at the specified location, an error occurs.

Exit

 prog.java:14: Error: Unregistered FileNotFoundException; must be caught or declared abandoned    FileReader reader = new FileReader types ("file.txt");                        ^prog.java:25: Error: Miscellaneous IOExceptions not reported; must be caught or declared to be thrown     ((Br data = .readLine ())! = Null)                              ^prog.java:31: Error: Unregistered IOException; must be found or advertised to run   Br .close ();            ^3 errors 

If the specified file is not available for the example, if it is read-only, then the client can read the file but not convert the filewhen we try to configure it, it will lead to an error when trying to access the read / write operation from another program, this error must necessarily occur.

Exit

 java.security.AccessControlException: access denied (file "java.io.FilePermission". "write") txt "to java.base / java.security.AccessControlContext.checkPermission (AccessControlContext.java:472)    at java.base / java.security.AccessController.checkPermission (AccessController.java:897)    a cup of coffee in .base / java.lang.SecurityManager.checkPermission (SecurityManager.java:322)    at java.base / java.lang.SecurityManager.checkWrite (SecurityManager.java:752)    at java.base / java.io.FileOutputStream.  (FileOutputStream.java:225)   In java.base / java.io.FileOutputStream.  (FileOutputStream.java:187)    java at.base / java.io.FileWriter.  (FileWriter.java:96)   In Example2.main (File.java:19) 

First, we need to use a try-catch block when we know if an error occurs. All lines must be in the transmission block in case of any errors. There are other workarounds for handling the exception:

1. If the exception message indicates that most files or directories are not important, check again to see if you have specified the most important incorrect file name in the program, or if the file exists in the directory and does not.
2. If the exception message reports For people that access is denied, we need to check the access rights to the image (read, write, read and write), and also check if this file is being used by another program.
3. If the exception message tells us that the required file is a directory, you want to either delete the existing directory (if the folder is not in use) or initiate a change to the file.

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FileNotFoundException is thrown by the constructors FileInputStream, FileOutputStream, RandomAccessFile if the file with the specified path is not found. An exception can also be made if the file is not available for this reason. For example: if you do not have enough rights to read the files.

FileNotFoundException is a tested exception, so you need to create a handle usingMy Java code. You must take appropriate steps to throw an appropriate client exception if a FileNotFoundException is thrown.

java.io.FileNotFoundException: C: /Java2blog.txt (no such or file directory)
at java.base / java.io.FileInputStream.open0 (native method)
at java.base / java.io.FileInputStream.open (FileInputStream.java:196)
at java.base / java.io.FileInputStream. (FileInputStream.java:139)
at org.arpit.java2blog.FileReadExample.main (FileReadExample.java:17)
Exception on “main” thread java.lang.NullPointerException
at org.arpit.java2blog.FileReadExample.main (FileReadExample.java:27)

As anyone can see if the file is out of date in the path, we get FileNotFoundException

How To Fix FileNotFoundException

• Check if the passed file exists in the specified file.
• Make sure the file is indeed a directory.
• The uploaded file cannot and should not be opened due to permission issues. You can try writing to wake up as you only have permission to study.
• Make sure the uploaded file name does not contain invisible characters such as r n.

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Package org.arpit.java2blog; Import java.io.File; Import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; / ** * Example FileNotFoundException * @author Arpit * * / public class sample reading a public file Noise void main (String [] args *; try fis = = new FileInputStream (file); System off) e.printStackTrace (); trap (IOException e) Try it Fis .close (); trap (IOException e) e.printStackTrace ();

 

 

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